Optimal. Leaf size=185 \[ \frac {2 d^{5/2} (b c-a d) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {e+f x}}{\sqrt {d e-c f}}\right )}{(d e-c f)^{9/2}}-\frac {2 d^2 (b c-a d)}{\sqrt {e+f x} (d e-c f)^4}-\frac {2 d (b c-a d)}{3 (e+f x)^{3/2} (d e-c f)^3}-\frac {2 (b c-a d)}{5 (e+f x)^{5/2} (d e-c f)^2}-\frac {2 (b e-a f)}{7 f (e+f x)^{7/2} (d e-c f)} \]
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Rubi [A] time = 0.17, antiderivative size = 185, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {78, 51, 63, 208} \[ -\frac {2 d^2 (b c-a d)}{\sqrt {e+f x} (d e-c f)^4}+\frac {2 d^{5/2} (b c-a d) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {e+f x}}{\sqrt {d e-c f}}\right )}{(d e-c f)^{9/2}}-\frac {2 d (b c-a d)}{3 (e+f x)^{3/2} (d e-c f)^3}-\frac {2 (b c-a d)}{5 (e+f x)^{5/2} (d e-c f)^2}-\frac {2 (b e-a f)}{7 f (e+f x)^{7/2} (d e-c f)} \]
Antiderivative was successfully verified.
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Rule 51
Rule 63
Rule 78
Rule 208
Rubi steps
\begin {align*} \int \frac {a+b x}{(c+d x) (e+f x)^{9/2}} \, dx &=-\frac {2 (b e-a f)}{7 f (d e-c f) (e+f x)^{7/2}}-\frac {(b c-a d) \int \frac {1}{(c+d x) (e+f x)^{7/2}} \, dx}{d e-c f}\\ &=-\frac {2 (b e-a f)}{7 f (d e-c f) (e+f x)^{7/2}}-\frac {2 (b c-a d)}{5 (d e-c f)^2 (e+f x)^{5/2}}-\frac {(d (b c-a d)) \int \frac {1}{(c+d x) (e+f x)^{5/2}} \, dx}{(d e-c f)^2}\\ &=-\frac {2 (b e-a f)}{7 f (d e-c f) (e+f x)^{7/2}}-\frac {2 (b c-a d)}{5 (d e-c f)^2 (e+f x)^{5/2}}-\frac {2 d (b c-a d)}{3 (d e-c f)^3 (e+f x)^{3/2}}-\frac {\left (d^2 (b c-a d)\right ) \int \frac {1}{(c+d x) (e+f x)^{3/2}} \, dx}{(d e-c f)^3}\\ &=-\frac {2 (b e-a f)}{7 f (d e-c f) (e+f x)^{7/2}}-\frac {2 (b c-a d)}{5 (d e-c f)^2 (e+f x)^{5/2}}-\frac {2 d (b c-a d)}{3 (d e-c f)^3 (e+f x)^{3/2}}-\frac {2 d^2 (b c-a d)}{(d e-c f)^4 \sqrt {e+f x}}-\frac {\left (d^3 (b c-a d)\right ) \int \frac {1}{(c+d x) \sqrt {e+f x}} \, dx}{(d e-c f)^4}\\ &=-\frac {2 (b e-a f)}{7 f (d e-c f) (e+f x)^{7/2}}-\frac {2 (b c-a d)}{5 (d e-c f)^2 (e+f x)^{5/2}}-\frac {2 d (b c-a d)}{3 (d e-c f)^3 (e+f x)^{3/2}}-\frac {2 d^2 (b c-a d)}{(d e-c f)^4 \sqrt {e+f x}}-\frac {\left (2 d^3 (b c-a d)\right ) \operatorname {Subst}\left (\int \frac {1}{c-\frac {d e}{f}+\frac {d x^2}{f}} \, dx,x,\sqrt {e+f x}\right )}{f (d e-c f)^4}\\ &=-\frac {2 (b e-a f)}{7 f (d e-c f) (e+f x)^{7/2}}-\frac {2 (b c-a d)}{5 (d e-c f)^2 (e+f x)^{5/2}}-\frac {2 d (b c-a d)}{3 (d e-c f)^3 (e+f x)^{3/2}}-\frac {2 d^2 (b c-a d)}{(d e-c f)^4 \sqrt {e+f x}}+\frac {2 d^{5/2} (b c-a d) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {e+f x}}{\sqrt {d e-c f}}\right )}{(d e-c f)^{9/2}}\\ \end {align*}
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Mathematica [C] time = 0.06, size = 86, normalized size = 0.46 \[ -\frac {2 \left (7 f (e+f x) (b c-a d) \, _2F_1\left (-\frac {5}{2},1;-\frac {3}{2};\frac {d (e+f x)}{d e-c f}\right )+5 (b e-a f) (d e-c f)\right )}{35 f (e+f x)^{7/2} (d e-c f)^2} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.59, size = 1396, normalized size = 7.55 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 1.29, size = 450, normalized size = 2.43 \[ -\frac {2 \, {\left (b c d^{3} - a d^{4}\right )} \arctan \left (\frac {\sqrt {f x + e} d}{\sqrt {c d f - d^{2} e}}\right )}{{\left (c^{4} f^{4} - 4 \, c^{3} d f^{3} e + 6 \, c^{2} d^{2} f^{2} e^{2} - 4 \, c d^{3} f e^{3} + d^{4} e^{4}\right )} \sqrt {c d f - d^{2} e}} - \frac {2 \, {\left (105 \, {\left (f x + e\right )}^{3} b c d^{2} f - 105 \, {\left (f x + e\right )}^{3} a d^{3} f - 35 \, {\left (f x + e\right )}^{2} b c^{2} d f^{2} + 35 \, {\left (f x + e\right )}^{2} a c d^{2} f^{2} + 21 \, {\left (f x + e\right )} b c^{3} f^{3} - 21 \, {\left (f x + e\right )} a c^{2} d f^{3} + 15 \, a c^{3} f^{4} + 35 \, {\left (f x + e\right )}^{2} b c d^{2} f e - 35 \, {\left (f x + e\right )}^{2} a d^{3} f e - 42 \, {\left (f x + e\right )} b c^{2} d f^{2} e + 42 \, {\left (f x + e\right )} a c d^{2} f^{2} e - 15 \, b c^{3} f^{3} e - 45 \, a c^{2} d f^{3} e + 21 \, {\left (f x + e\right )} b c d^{2} f e^{2} - 21 \, {\left (f x + e\right )} a d^{3} f e^{2} + 45 \, b c^{2} d f^{2} e^{2} + 45 \, a c d^{2} f^{2} e^{2} - 45 \, b c d^{2} f e^{3} - 15 \, a d^{3} f e^{3} + 15 \, b d^{3} e^{4}\right )}}{105 \, {\left (c^{4} f^{5} - 4 \, c^{3} d f^{4} e + 6 \, c^{2} d^{2} f^{3} e^{2} - 4 \, c d^{3} f^{2} e^{3} + d^{4} f e^{4}\right )} {\left (f x + e\right )}^{\frac {7}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.02, size = 281, normalized size = 1.52 \[ \frac {2 a \,d^{4} \arctan \left (\frac {\sqrt {f x +e}\, d}{\sqrt {\left (c f -d e \right ) d}}\right )}{\left (c f -d e \right )^{4} \sqrt {\left (c f -d e \right ) d}}-\frac {2 b c \,d^{3} \arctan \left (\frac {\sqrt {f x +e}\, d}{\sqrt {\left (c f -d e \right ) d}}\right )}{\left (c f -d e \right )^{4} \sqrt {\left (c f -d e \right ) d}}+\frac {2 a \,d^{3}}{\left (c f -d e \right )^{4} \sqrt {f x +e}}-\frac {2 b c \,d^{2}}{\left (c f -d e \right )^{4} \sqrt {f x +e}}-\frac {2 a \,d^{2}}{3 \left (c f -d e \right )^{3} \left (f x +e \right )^{\frac {3}{2}}}+\frac {2 b c d}{3 \left (c f -d e \right )^{3} \left (f x +e \right )^{\frac {3}{2}}}+\frac {2 a d}{5 \left (c f -d e \right )^{2} \left (f x +e \right )^{\frac {5}{2}}}-\frac {2 b c}{5 \left (c f -d e \right )^{2} \left (f x +e \right )^{\frac {5}{2}}}-\frac {2 a}{7 \left (c f -d e \right ) \left (f x +e \right )^{\frac {7}{2}}}+\frac {2 b e}{7 \left (c f -d e \right ) \left (f x +e \right )^{\frac {7}{2}} f} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.36, size = 218, normalized size = 1.18 \[ \frac {2\,d^{5/2}\,\mathrm {atan}\left (\frac {\sqrt {d}\,\sqrt {e+f\,x}\,\left (c^4\,f^4-4\,c^3\,d\,e\,f^3+6\,c^2\,d^2\,e^2\,f^2-4\,c\,d^3\,e^3\,f+d^4\,e^4\right )}{{\left (c\,f-d\,e\right )}^{9/2}}\right )\,\left (a\,d-b\,c\right )}{{\left (c\,f-d\,e\right )}^{9/2}}-\frac {\frac {2\,\left (a\,f-b\,e\right )}{7\,\left (c\,f-d\,e\right )}-\frac {2\,\left (e+f\,x\right )\,\left (a\,d\,f-b\,c\,f\right )}{5\,{\left (c\,f-d\,e\right )}^2}-\frac {2\,d^2\,{\left (e+f\,x\right )}^3\,\left (a\,d\,f-b\,c\,f\right )}{{\left (c\,f-d\,e\right )}^4}+\frac {2\,d\,{\left (e+f\,x\right )}^2\,\left (a\,d\,f-b\,c\,f\right )}{3\,{\left (c\,f-d\,e\right )}^3}}{f\,{\left (e+f\,x\right )}^{7/2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 60.09, size = 168, normalized size = 0.91 \[ \frac {2 d^{2} \left (a d - b c\right )}{\sqrt {e + f x} \left (c f - d e\right )^{4}} + \frac {2 d^{2} \left (a d - b c\right ) \operatorname {atan}{\left (\frac {\sqrt {e + f x}}{\sqrt {\frac {c f - d e}{d}}} \right )}}{\sqrt {\frac {c f - d e}{d}} \left (c f - d e\right )^{4}} - \frac {2 d \left (a d - b c\right )}{3 \left (e + f x\right )^{\frac {3}{2}} \left (c f - d e\right )^{3}} + \frac {2 \left (a d - b c\right )}{5 \left (e + f x\right )^{\frac {5}{2}} \left (c f - d e\right )^{2}} - \frac {2 \left (a f - b e\right )}{7 f \left (e + f x\right )^{\frac {7}{2}} \left (c f - d e\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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